Hello all Today I am going to post about the topic Coloumbs law Of Electrical Force
Coloumbs Law of Electrical Force :
According to this law The electrostatic force between two point charges is directly proportional to the product of their magnitudes and inversily proportional to the square of distance between their centres
This force will be repulsive or attractive depending upon whether the charges are like or unlike further
The force always acting along the line joining the centres of two charges
Consider two point charges Q1 and Q2 hold "d" distance apart in vacuum
According to Coloumbs law the magnitude of electrostatic force between the charges is given by
Where 'k' is a Constant whose value depends upon the system of units employed and the nature of the medium
The SI units when placed in vacuum
k= 1/(4πε0)
=1/(4π×8.854×10^(-12))
=9×10^9
Where
ε0= Absolute Permittivity of space
=8.854×10^(-12) F/M
F= (1/4πε0)×(Q1Q2/d^2)
*The direction of forces that one charge exerts on another is determined by considering the relative signs of charges
Relative Permittivity Or Dielectric Constant
Permittivity is the property of a medium and effects the magnitude of force between two point charges
•Air or vaccum has minimum values of Permittivity
The absolute Permittivity of all other insulating materials is greater than 'ε0'
εr = ε/ε0
=Absolute Permittivity of the medium / Absolute Permittivity of the Air or Vaccum
Then
Force
F=(1/4πε0εr)×(Q1Q2/d^2)
Hence , relative Permittivity (or Dielectric Constant) of a medium may be defined as the ratio of force between two charges separated by the same distance in the medium
Coloumbs Law of Electrical Force :
According to this law The electrostatic force between two point charges is directly proportional to the product of their magnitudes and inversily proportional to the square of distance between their centres
This force will be repulsive or attractive depending upon whether the charges are like or unlike further
The force always acting along the line joining the centres of two charges
Consider two point charges Q1 and Q2 hold "d" distance apart in vacuum
According to Coloumbs law the magnitude of electrostatic force between the charges is given by
Where 'k' is a Constant whose value depends upon the system of units employed and the nature of the medium
The SI units when placed in vacuum
k= 1/(4πε0)
=1/(4π×8.854×10^(-12))
=9×10^9
Where
ε0= Absolute Permittivity of space
=8.854×10^(-12) F/M
F= (1/4πε0)×(Q1Q2/d^2)
*The direction of forces that one charge exerts on another is determined by considering the relative signs of charges
Relative Permittivity Or Dielectric Constant
Permittivity is the property of a medium and effects the magnitude of force between two point charges
•Air or vaccum has minimum values of Permittivity
The absolute Permittivity of all other insulating materials is greater than 'ε0'
εr = ε/ε0
=Absolute Permittivity of the medium / Absolute Permittivity of the Air or Vaccum
Then
Force
F=(1/4πε0εr)×(Q1Q2/d^2)
Hence , relative Permittivity (or Dielectric Constant) of a medium may be defined as the ratio of force between two charges separated by the same distance in the medium
- For air or Vaccum εr=ε0/ε0 = 1
- εr is a number being a ratio of two absolute permittivities
Please Comment Below For Any Doubts .....
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